include <stdio.h>int main(){int i,j,n=0;i=1;do{j=1;while(j<=5){if (n%5==0) printf ("\n"); printf("%5d",i*j);j++,n++;} }while(++i<=4); printf("\n"); return 0;}这样就好了
int a[3][2]={(0,1),(2,3),(4,5)};int a[3][2]={{0,1},{2,3},{4,5}};两种方式赋值不同，第一种数组的值分别为1,3,5,0,0,0,第二种是0,1,2,3,4,5 应该
#include<stdio.h> main() { int a,b;int c=0; scanf("%d",&a); while(a>0) { b=a%10; if (b%2==0) c=c+b; a=a/10; } printf("%d",c); getch(); return 0; } 本回答被网友采纳 已赞过 已踩过< 你对这个回答的评价是? 评论 收起 你猜我猜哇擦猜 2015-11-02 · TA...
c,b,a);}}getch();}include<stdio.h>void main (){int a,b,c,sum;printf("please input:");scanf("%d%d%d",&a,&b,&c);if(a>b){if(b>c){printf("%d>%d>%d",a,b,c);}else if(b<c) //在这里多加一步判断{if(a>c){printf("%d>%d>%d",a,c,b);}else{printf("...
sizeof(int),1,fp);cout<<"0x"<<setw(8)<<hex<<setfill('0')<<setiosflags(ios::right)<<swap1(a)<<endl;//方法一cout<<"0x"<<setw(8)<<setfill('0')<<setiosflags(ios::right)<<swap2(a)<<endl;//方法二}return 0;}include <stdio.h>int main(void){FILE* fp;long int...
最后a就变成了11有到类似的题是这样的int *p=&a,a=10,b=1;a=*p+b;我举例的这道题选的是D而你这道类似，所以选择Dinclude<stdio.h>void main(){int *p,a=10,b=1p=&a;a=*p+b;printf("%d",a);}Compiling...Cpp1.cppC:\Users\Lenovo\Desktop\Cpp1.cpp(5) : error C2146: ...
include <stdio.h> int main(int argc, char *argv[]){ int k,m,n;// 重定向输入流 freopen("data.txt","r",stdin);while(scanf("%d",&k)!=EOF){ for(m=k+1;m<=2*k;m++){ // 判断 km/(m-k) 是整数 if(k*m%(m-k) == 0){ n = k*m/(m-k);printf("1/%d ...
include<stdio.h> int main(){ int max(int x,int y);int a,b,c;printf("please enter two integer numbers:");scanf("%d,%d",&a,&b);c=max(a,b);printf("max is %d\n",c);return 0;} int max(int x,int y){ int z;z=x>y? x:y;return(z);} ...
你好，我来回答吧！include<stdio.h> main(){ int n,sum=0;scanf("%d",&n);while(n>=3)sum+=n--;printf("sum=%d\n",sum);} 首先分析你的代码，这是一个很基础的c代码，首先输入n，你输入的是3，那么n=3；开始进入循环，n>=3满足条件，进入循环体，进入关键句了，sum+=n--；这...
include<stdio.h> int main(){ int i,m=0;for(i=2;i<=100;i+=2) m=m+i;printf("%d\n",m);return 0;} 或 include int main(){ int i,sum=0;for(i=1;i<=50;i++){ sum=sum+2*i;} printf("2+4+6+…+98+100=%d\n",sum);return 0;} ...