MOV AH,2 MOV DL,0AH INT 21H MOV CX,4 L3: PUSH CX MOV CL,4 ROL BX,CL MOV DL,BL AND DL,0FH ADD DL,30H CMP DL,39H JBE L4 ADD DL,7 L4: MOV AH,2 INT 21H POP CX LOOP L3 JMP L6 L5:MOV AH,9 LEA DX,ERROR INT 21H L6:MOV AH,4CH INT 21H ERROR DB 0DH,0AH,"0VERFLOW...
STRING1 DB 'please input a string1:$'STRING2 DB 'please input a string2:$'STRING3 DB 'MATCH!$'STRING4 DB 'NO MATCH!$'BUF1 DB 20 ,?, 20 DUP (?)BUF2 DB 20 ,?, 20 DUP (?)CRLF DB 0AH,0DH,"$"DATAS ENDS STACKS SEGMENT STACK DB 200 DUP(?)STACKS ENDS CODE...
after db 'after sort:', 13,10,'$'odd db 'sum of odd: $'even db 'sum of even: $'so dw 0 se dw 0 imacro invoke 1- rep %0-1 rotate -1 push %1 endrep rotate -1 call %1 endmacro imacro msg 1 mov ah, 9 mov dx, %1 int 21h endmacro s...
CODE SEGMENT ASSUME CS:CODE STRING DB 'what are you doing?','$' START: PUSH CS POP DS MOV DL,0DH MOV AH,2 INT 21H MOV DL,0AH MOV AH,2 INT
MOV DL,0DH;调用DOS中断字符输出，输出字符ASCLL是0DH，即换行符 MOV AH,02H;中断功能号02H INT 21H;DOS中断,21H MOV DL,0AH;调用DOS中断字符输出，输出字符ASCLL是0AH，即回车 MOV,AH,02H;中断功能号02H INT 21H;;DOS中断,21H ENDM ;宏定义结束 DATA SEGMENT ;数据段 DATA1 DB 33H,39H...
mov ah,02h mov dl,0dh int 21h mov dl,0ah int 21h pop dx pop ax ret Enter_CTLF endp ; －－－ ; 功能：统计小写字母个数 ; 入口：SI=字符串地址 ; 出口：BL=小写字母个数 Stitics proc Near push cx push ax lodsb ;读入实际输入的字符个数 mov cl,al xor ...
add2db6 db?db6 dup (?)numdw?; 存放中间结果 signdb?; 两个数和的符号位 sumdw10 dup (?); 两个数的和 datasg ends stacksg segment stacksg ends codesg segment start:movax,datasg movds,ax leadx,input1 movah,9 int21h ; 读取第一个加数 movdx,offset add1 movah,10 int21h...
; 本程序通过编译，运行正确。DATA SEGMENT MES1 DB '92,85,74,81,70,68,65,78,54,43',0AH,0DH DB '94,100,83,88,79,83,79,69,62,60',0AH,0DH,'$' ;定义用于显示的字符串 MES2 DW 92,85,74,81,70,68,65,78,54,43 DW 94,100,83,88,79,83,79,69,62,60 ;存放20个...
big enough msg90 db 'Number (>=90): $' msg60 db 0dh, 0ah, 'Number (<60): $' msgmax db 0dh, 0ah, 'Max Score : $' msgmin db 0dh, 0ah, 'Min Score : $'dseg endscseg segmentstart: mov ax, dseg mov ds, ax mov cx, len ;30 students lea si, ...
第二个实现的功能跟第一个类似 这一句出现了致命了错误 MUL IBUF,乘数是一个数，而你的IBUF定义了一串的数，系统分辨不出来，第一个帮你解释一下 --- data segment buf db 0ah,0dh,'shu ru shu zi:$' ;提示信息 b_x db 10 ;为输入部分做准备，定义一个B_X变量，数值为10 data end...