应该是你想复杂 了..我根据你写的改了一下..你看看跟你的有什么区别..include<stdio.h> int main(void){ int a[10];int n,i,k,temp;printf("enter n:");scanf("%d",&n);printf("enter %d :",n);for(i=0;i<n;i++){ scanf("%d",&a[i]);} for(k=0;k<n;k++){ for...
dim i as integer dim j as integer dim temp as integer '输入一个正整数n(1<n<=10)n = Val(InputBox("输入一个正整数[2,10]："))Do While n < 2 Or n > 10 n = Val(InputBox("输入一个正整数[2,10]：", "输入错误，请重新输入！"))Loop ReDim d(n)'输入n个正整数保存...
include<stdio.h>#include<malloc.h>int main(){ int n,*num,i,sum=0; printf("输入正整数n的值(1＜n＜=10)："); scanf("%d",&n); num=(int *)malloc(sizeof(int)*n); printf("输入%d个整数：",n); for(i=0;i<n;i++) { scanf("%d",&num[...
c语言程式设计：阵列：输入一个正整数n，再输入n个正整数并从大到小排序输出。 采用冒泡法，C语言书上应该有这样的例子的。原理其实很简单，就是将每个数依次比较，每次取最大的数，全部比较完成，就输出来，然后再比较剩下的。C语言 从键盘输入10个整数，将这10个整数按从小到大的顺序输出。 #...
include"stdio.h"void main(){ int i,n,num;float sum = 0;printf("输入一个正整数：");scanf("%d",&n);for (i = 1; i <=n; i++){ printf("输入第%d个整数:\n", i);scanf("%d",&num);sum = sum + num;} printf("%d个整数的平均数为：%.2f\n", n, sum/n);} ...
include<stdio.h>int main(){int i,n,a[100],max; scanf("%d",&n); for(i=0;i<n;i++) {scanf("%d",&a[i]); if(i==0)max=a[i]; if(max
include<stdio.h> int main(){ int n,i,ave;int sum=0;int a[];printf("请输入一个整数n(1≤n≤10)：");scanf("%d",&n);for(i=0;i<n;i++){ scanf("%d",&a[i]);sum=sum+a[i];} ave=sum/n;printf("the result is %d",ave);return 0;} ...
include <stdio.h> int main(){ int ma=0,mi;for(int i=1,x;i<=10;i++){ scanf("%d",&x);if(x>ma){ ma=x;mi=i;} } printf("%d %d",mi,ma);return 0;} 望采纳，谢谢
include<stdio.h> void main(){ int n,i,a[10],index;scanf("%d",&n); for ( i=0;i<n;i++ ) scanf("%d",&a[i]);index=0; for ( i=1;i<n;i++ ) if ( a[i]>a[index] ) index=i;printf("max=%d, index=%d\n",a[index],index);} ...
include <stdio.h>void fun(int a[100],int n){int i,t;for(i=0;i<n/2;i++){t=a[i];a[i]=a[n-i-1];a[n-i-1]=t;}}void main(){int i,n,a[100];scanf("%d",&n);for(i=0;i<n;i++)scanf("%d",&a[i]);fun(a,n);for(i=0;i<n;i++)printf("%d "...