include<stdio.h>#include<math.h> int main(){int a,b,c;float d,e,f;//这里最好用double类型，后面printf将%.2f改成%.2lfscanf("%d %d %d",&a,&b,&c);f = b*b-4.0*a*c;if(f>0)//实根，不能先开方在相乘，俩负数相乘也是正数{d = (-b-sqrt(f))/(2*a);e = (-...
include <stdio.h> #include <math.h> int main() {int a,b;float c;printf(" ");for(a=0;a<10;a++)printf("%6d",a);printf("\n");for(a=0;a<10;a++){ printf("%6d",a);for(b=0;b<10;b++){c=sqrt(10*a+b);printf("%6.3f",c);}printf("\n");}return...
include "stdafx.h"include<math.h> int main(int argc, char* argv[]){ float a ,b;a=20.0;b=sqrt(a);printf("%f",b);} 定义成浮点型就可以算了
int main(){ int a,b,c;float s,t,r,x1,x2;printf("please input a b c:"); // 输入格式a b c 之间无逗号，这里提示 也不要写逗号 scanf("%d%d%d",&a,&b,&c);// a==0 和 b==0 的情况处理 if (a==0) { if (b==0) {printf("no result\n"); return 0;} ...
定义一个变量a,接受键盘输入和变量sum保存a的各位数字之和,并依次对a进行除10操作,把a除10的余数加到sum中,直到a为0为止,sum最终的值就是a个位数字之和。 #include<math.h>#include<stdio.h>int main(){int a,sum=0;scanf("%d",&a);while(a){sum+=a%10;a/=10;}printf("%d\n...
include <math.h> int main() { int a, b, c, d;float mean, variance;printf("请输入4个整数：\n");scanf("%d %d %d %d", &a, &b, &c, &d);mean = (float)(a + b + c + d) / 4;variance = ((a - mean) * (a - mean) + (b - mean) * (b - mean) + ...
include<math.h> main(){ int a,b,c;double DT,x,x1,x2;scanf("%d %d %d",&a,&b,&c);DT=b*b-4*a*c;if((a==0)&&(b==0))printf("Input error!\n");else { if(a==0){x=-c/(1.*b);printf("x=%.6f\n",x);} else { if(DT==0){x=-b/(2*a);printf("...
include<math.h> int main(){ int a,b,c;float d,v1,v2;scanf("%d %d %d",&a,&b,&c);d = b*b - 4*a*c;if (d > 0) { v1 = (-b + sqrt(d)) /2.0/a;v2 = (-b - sqrt(d)) /2.0/a;printf("v1=%f v2=%f\n",v1,v2);}else if (d==0){ v1= -b...
include<stdio.h> int main(){ int a,b;float x,y;char c1,c2;scanf("%d%d",&a,&b);//不要添加多余字符 scanf("%f%f",&x,&y);//float类型用%f getchar(); // 添加此句接收上一句按下的回车符 scanf("%c%c",&c1,&c2);//输入这两字符时需连在一起 输入 printf("%d ...
晕了，线代对上，下三角矩阵的定义就是在N阶矩阵的范围内定义的，当然属于方阵