int n;int a[maxn],b[2*maxn];long sum[maxn][maxn];long globalmax = 0;void Initialize(){ int i;FILE *fin = fopen("energy.in","r");fscanf(fin,"%d",&n);for (i=1;i<=n;i++)fscanf(fin,"%d",&a[i]);fclose(fin);} void predoing(int s){ int i,j;for ...
intc=b/4;//c=4intd=b-c;//d=14inte=-d;//e=-14intf=e%4;//f=-2doubleg=18.4;doubleh=g%4;//h=2.4inti=3;intj=i++;//i=4,j=3intk=++i;//i=5,k=5System.out.println("a="+a);System.out.println("b="+b);System.out.println("c="+c);...
魂淡 ，你还没说用什么语言编写呢，我就用C给你写一下 int qiuhe(a,n){ int sum,i,j;sum=a;j=a;for(i=1;i<n;i++){ a=a*10+j;sum=sum+a };return sum } 如果n的值比较大的话 ，就把变量都定义为float或double类，防止溢出。
5]); //定义方差函数int main(){ int stu[10][5]; int i, j; for (i=0; i<10; i++) for (j=0; j<5; j++) scanf("%d", &stu[i][j]); //输入10个学生各5门课的成绩 aver_stu(stu);
for循环:main(){int i=1,n,sum=0;printf("input n=");scanf("%d",&n);for(;i<=n;i++)sum=sum+10*i+2;printf("sum=%d",sum);getch();} while循环:main(){int i=1,sum=0,n;printf("input n=");scanf("%d",&n);while(n){sum=sum+10*i+2;i++;n--;} printf("...
int i=0j=0,t,a[80l;while(n!=0) {ali]=n%10; n/=10; i++;] i-- while(j<i/2) {t=a[j+i-1];alj+i-1]=aljl; aljl=t;] (2) 先求出位数再逆序输出 int a,i=1,m,x,n,y;scanf("%d",&a);while (m!=0){m=a/pow(10,i); i++;}x=a; for(i=i-1;i>0;i--){...
(D=-t,h=P); for(i=M; P>i; i+=3){ B(C,i); a(C,Q); b=H(E,C); (t=b*b-H(C,C)+(i<L?99 :.6))>=0&&0<(t=b<t?t+b:b-t)&&D>t&&(D=t,h=i); } return h; } void Y(int N){ F*h,*i; A p,n; if(!(h=d()))*c=1[c]=(2[c]=2[E]/2)/2;...
int java;int pc;int aver;int total;}main(){int i=0;int j=0;int sum=0;int av;int choice;char ch,n[20];struct students temp;struct students stu[3];ml:clrscr();printf("***WELCOM TO THE STUDENTS INFORMATION System***\n");printf(" * 1:Lookfor students by name *\n");printf...
public static void unique(int[] arr) {if (arr == null || arr.length < 2) return;for (int i = 0; i < arr.length; i++) {//依次取得每个元素if (arr[i] == 0) continue;//遇到0，表示无需处理或已经被替换过boolean flag = false;for (int j = i + 1; j < arr....
integerCacheHighPropValue);i=Math.max(i,127);//MaximumarraysizeisInteger.MAX_VALUEh=Math.min(i,Integer.MAX_VALUE-(-low)-1);}catch(NumberFormatExceptionnfe){//Ifthepropertycannotbeparsedintoanint,ignoreit.}}high=h;cache=newInteger[(high-low)+1];intj=low;for(intk=0;...