sum); }<1>main(){int i=2,sum=0;while(i<101){sum+=i;i+=2;}printf("1~100之间所有的偶数的和是:%d\n",sum);}<2>main(){int i,sum=0;for(i=2;
include <stdio.h>void main(){int i,s=0;for(i=1;i<=20;i++) s+=(i%2)?0:i;printf("s=%d",s);} 运行结果截图:include <stdio.h>int main(){ int i,sum = 0; for( i = 2 ; i <= 20 ; ++i,++i ){ sum += i; } printf("sum = %d\n",sum...
include<iostream.h> int main(){int num[100],j=3;int i,sum;sum=0;num[0]=2;for(i=1;i<100;i++){num[i]=j;j+=2;}for(i=0;i<99;i++)if(num[i])for(j=i+1;j<100;j++)if(num[j]&&num[j]%num[i]==0)num[j]=0;j=0;for(i=0;i<100;i++)if(num[i])...
printf("结果是:%d\n",s);}代码如下,不明白追问!include<stdio.h>int main(void){int i, M, N;long int sum = 0;printf("请输入两个正整数M、N:\n");scanf("%d %d",&M,&M);printf("你输入的M = %d N = %d\n", M, N);if(M > N){i = M;M = N;N = i;}for...
1、输入一个正整数 n (1<n<=10),再输入n 个整数,输出平均值(保留2 位小数)。sum = 0;for(i = 0;i < n;i++){ sum += a[i];} aver=sum*1.0/n;2、index = 0;for(i = 1;i < n;i++){ if(a[i] > a[index]){ index = i;} } 命题 1 对于B=36N+1 形数...
int main() { int i,sum=0; //定义两个整型变量 { for(i=1;i<=100;i=i+2) //变量i的for循环从1开始,直到99为止 sum=sum+i; //变量i累加 } printf("1+3+--+99=%d\n",sum); //输出奇数和结果 return...
Action(){ int i,j;int sum=0;int flag;//是否为素数 for(i=2;i<=100;i++){ flag=1;for(j=2;j<=i-1;j++){ if(i%j==0){ flag=0;break;} } if(flag==1){ sum+=i;} } lr_output_message("sum=%d",sum);return 0;} 输出的结果:sum=1060 ...
include<stdio.h> int main(){ int n,i;int sum=0;printf("请输入要累加的数字n:");scanf("%d",&n);for(i=0;i<=n;i++){ sum=sum+i;} printf("累加的和为%d",sum);return 0;}
int main(){ int sum=0,i;for (i=2;i<=100;i=i+2)sum=sum+i;printf("2+4+6...+100=%d\n",sum);return 0;} include "stdio.h"include "string.h"int main(){ char s1[6]={};char s2[6]={'w','a','t','e','r','\0'};int i;printf("输入字符串: \n");ge...
include <stdio.h>include <stdlib.h>include <math.h>int main(){double i;double times;double sum1,sum2;printf("指定的次数:");scanf("%lf",×);sum1=0;sum2=0;while (times>0){for (i=1.0;i<=times;i++){sum1=sum1+1.0/i ;sum2=sum2+pow(-1.0,i+1.0)*1.0...