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...{2,2}, {2,2,2}}; int sum=0; for(int i=0;i<b.length;i++) {...

"相关结果约100,000,000个

输入n,m和数组元素的c语言是什么?

```c include <stdio.h> int main() { int n, m;printf("Enter the value of n: ");scanf("%d", &n);printf("Enter the value of m: ");scanf("%d", &m);int arr[n];printf("Enter %d elements:\n", n);for (int i = 0; i < n; i++) { scanf("%d", &arr[i...

利用循环结构编程序求1+2+3+···+n的和并输出,其中n由键盘输入_百度...

cout<<"请输入参数n:";cin>>n;for(int i=1;i<=n;++i)sum+=i;cout<<endl<<"1+2+3+···+n="<<sum;include "stdio.h"void main(){int n,sum,i;sum=0;scanf("%d",&n);for(i=1;i<=n;i++)sum+=i;printf("1+2+3+···+%d=%d\n",n,sum);}include<stdio....

int sum = 0; for ( int i=0; i<10; i++ ) { if ( i%2 ) continue; su...

continue语句只结束本次循环,而不终止整个循环的执行。而break语句则是结束整个循环过程,不再判断执行循环的条件是否成立。0%2=0,整个程序大概是一开始进入for循环,然后到if,遇到continue,则程序继续往下,遇到break,则是结束循环,也就是不在进行for循环,跳到 Console.WriteLine(i);continue...

用c++编写

void Input(int n[][6]){ for(int i=0;i<6;i++){ for(int j=0;j<6;j++){ cin>>n[i][j];} } } double Average(int *ip,int n){ double sum=0;for(int i=0;i<n;i++)sum+=ip[i];return sum/n;} int Max(int (*a)[6],int n,int *r,int *l){ int max=...

求一c语言程序:输入一批正整数(以0或负数为结束标志)求其中偶数的和...

"<<endl;for(int i=0;i<10;i++){cin>>a[i];if(a[i]<=0){break;}else{sum+=a[i];}}cout<<"和为:"<<sum<<endl;system("pause");}include<stdio.h>int main(void){int i = 1,s = 0;while(1){scanf("%d",&i);if(i <= 0)break;if((i%2) == 0)s += i;...

用JAVA编写程序求1+3+7+…+(2的20次幂-1)的值 我编的程序哪错了?_百度...

第一次循环内,i=19时,al[i+1]就数组越界了所以这句al[i+1]=al[i]*2; 改成 al[i] = (i+1) * 2;还有你写的太复杂,直接public static void main(String[] args) {int sum = 0;for (int i = 0; i < 20; i++) {sum += (i + 1) * 2 - 1;}System.out.println("...

C语言.编写程序,输出50-100之间所有奇数的累加和?

```c include <stdio.h> int main() { int sum = 0;for (int i = 51; i < 100; i+=2) { sum += i;} printf("50到100之间所有奇数的累加和为:%d", sum);return 0;} ```代码解释:1. 使用“for”循环来遍历50到100之间的所有奇数。2. 初始化“sum”变量,将其赋值为0。...

编写程序,利用循环语句求2-4+6-8+…-100的值

include "stdio.h"main(){ int i,j=1,sum=0;for(i=2;i<=100;i+=2) ;{ sum+=j*i;j=-j;} printf("%-4d",sum);} include

帮忙看看这个C++题目啦!!

include<stdio.h>#include<string.h>int main(){int n,m,i,j;char sickman[101][101];printf("输入人数: ");scanf("%d",&n);memset(sickman,'#',sizeof(sickman)); //数组全部设为为'#',即无人住。不要这句也行 printf("输入字符数组:\n");for(i = 0; i < n; i++)...

C语言编程题,急,请大家帮忙啊,不会的也试试啊,急

\n", i);}}问题二:已知:X[12]={2,45,67,12,3,9,76,45,23,42,6,5},编程实现数组X中奇数的个数及奇数之和.源代码 b.cinclude <stdio.h>include <stdlib.h>main(){int X[12]={2,45,67,12,3,9,76,45,23,42,6,5}, sum=0, count=0;for(int i = 0; i <12; i ...
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