从大到小：include<stdio.h> define N 10 void main(){ int i,j;float a[N],t;printf("排序前:\n");for(i=0;i<N;i++){ scanf("%d",&a[i]);} for(i=0;i<N;i++){ printf("%6.1f",a[i]);} printf("\n");for(i=0;i<N-1;i++){ for(j=0;j<N-i-1;j++...
；s初值置0，累加每个n当前值时的阶乘t，就完成了题设要求。代码如下：include "stdio.h"int main(int argc,char *argv[]){ int s,n,t;for(s=0,t=n=1;n<11;s+=t*=n++);//用t记录每个n的当前值的阶乘并累加到s printf("1!+2!+3!+...+10! = %d\n",s); return 0;} ...
include<stdio.h> void main(){ int a[5]={0};int i,j,t;printf("请依次输入5个整数\n");for(i=0;i<5;i++) //输入5个数 scanf("%d",&a[i]);for(i=0;i<5;i++) //从大到小排序 for(j=i+1;j<5;j++)if(a[i]<a[j]){ t=a[i];a[i]=a[j];a[j]...
include <stdio.h>void main(){ int i,j,m=0,n=0; for(i=0;i<2;i++){ for(j=0;j<2;j++){ if（j>=i){ m=1; } } } n++; printf("%d\n",n);}上面是我给你整理的程序,还有,提醒一句,注意编程习惯
include<stdio.h> void main(){ printf("***|n");printf(" *** |n"); 前一个空格后一个空格 printf(" * |n"); 前两个空格后两个空格 } 空格也占空间 include
include <stdlib.h> void find(int *p,int *n, int x){ int i, j, src_len = *n;for(i = 0; i < src_len; i++){ if(p[i] == x){ j = i;while(j < src_len){ if(p[j+1] != x){ p[i] = p[j+1];(*n)--;break;}else{ j++;} } } } } int main...
include<stdio.h>int main() {int i,a,s=0;for(i=0;i<15;i++){scanf("%d",&a); s+=a;}printf("总和=%d\n",s);return 0;} include
include "stdio.h"int main(int argc,char *argv[]){int a[2][3],b[6],i,j,k;printf("Please enter data(int)...\n");for(k=i=0;i<2;i++){for(j=0;j<3;j++){scanf("%d",a[i]+j);printf("%d ",b[k++]=a[i][j]);}printf("\n");}printf("Out b...\n"...
---输出需要循环for (i=0;i<3;i++) for (j=0;j<3;j++) cout<<a[i][j]<<endl;int main(){int a[3][3]={1,2,3,4,5,6,7,8,9};int i,j;for(i=0;i<3;i++){for(j=0;j<i;j++){a[i][j]=0;}}for(i=0;i<3;i++){for(j=0;j<3;j++){cout << a...
include<stdio.h> include<string.h> int main(){ void num_space(char a[],char b[]);char a[100],b[100]="";printf("请输入任意四位数：");gets(a);num_space(a,b);printf("%s\n",b);return 0;} void num_space(char a[100],char b[100]){ int i,j=0;for(i=0;a[...