include<stdio.h> void main(){ int x,y;scanf("%d",x);if(0<x&&x<=2)y=x+1;if(x==0)y=x-1;if(-2<=x&&x<0)y=x;printf("y=%d",y);} 如果想输小数的话把int 改成float，把 %d改成%f，就行了 include
z的阶乘 static int s=0; scanf("%d %d %d",&x,&y,&z); a= factorial_(x); fact_num=1;//计算阶乘之前先把这个初始化一下 b= factorial_(y); fact_num=1; c= factorial_(z); s=a+b+c;//求和 return s;}void main(){ printf("%d\n",sum...
{z=(n*t%m+m-n+y);if(z>m) z=z-m;x=z;} else x=(n*t-n+y);return x;} void main(){int gac(int m,int n,int y,int t);int m,n,y,t,a;int x2,y2,t2,a2;printf("问题1\n请输入男女生的人数，以逗号隔开\n");scanf("%d,%d",&m,&n);printf("请输入此时...
我贴一个很有趣的冒泡排序思想的算法好了：include<stdio.h>int main(){int x,y,z,tmp;printf("请输入三个不同的数字,每输入一个数字用逗号隔开\n");scanf("%d,%d,%d",&x,&y,&z);if(x>y){tmp = x;x = y;y = tmp;}if(y>z){tmp = y;y = z;z = tmp;}if(x>y){...
include<stdio.h> int max_g(int m,int n)//最大公因数 { int r;r=m%n; //如果r=0,即m能将n整除,说明n为最大公因数 while(r!=0){ m=n;n=r;r=m%n;} return n;} void main(){ int x,y,z;printf("请输入分别两个数:\n");scanf("%d%d",&x,&y);z=max_g(x,...
手打这其实可以更简便的include"stdio.h"include"math.h"void main(){int x,i,j,k,m;scanf("%d",&x);for (i=1;i<=x;i++){m=abs(i-(x/2+1));for(k=1;k<=m;k++)printf(" ");for(j=2*(x/2+1);j>2*m+1;j--)printf("#");printf("\n");}}include<stdio.h>v...
else z=y;return (z);}include<stdio.h>int max(int x, int y);void main(){int a, b, c, d, e;scanf("%d,%d,%d",&a,&b,&c);d=max(a,b);e=max(c,d);printf ("%d %d %d 中最大的数是 %d", a,b,c,e);}int max(int x, int y){int z;if(x>y)z=x;else...
include <stdio.h>void output( int n ) //递归，正序输出每一位数{if ( n < 10 )printf("%d", n );else{output( n/10 );printf(" %d", n%10 );}}int main(){int i;printf("input n: ");scanf("%d", &i );output( i );printf("\n");return 0;}要求输入的数字，不...
int max,min;/*定义两个全局变量用于保存函数返回值*/ void max_min(int a,int b,int c) /*定义求最大最小值的函数*/ {max=min=a; /*初始化最大最小值*/ if(max if(max if(min>b)min=b;if(min>c)min=c;} main(){int x,y,z;printf(" 请输入3个整数：\n");scanf("%d...
x:y;}void main(){int a,b,c,mini;printf("please input first num:\n");scanf("%d",&a);printf("please input second num:\n");scanf("%d",&b);printf("please input third num:\n");scanf("%d",&c);mini=min(a,min(b,c));printf("the minimum is %d\n",mini);}...