include<iostream.h>int gcd(int a,int b){int r;if(a>b){int temp;temp=a;a=b;b=temp;};r=b%a;if(r==0)return a;else{ b=a;a=r;return gcd(a,b);};}void main(){int x,y,z;cout<<"Input three numbers x,y,z:"<<endl;cin>>x>>y>>z;cout<<"x,y的最大...
这道题是算法题，不能蛮算的，它有规律：乘积的最后三位值只与乘数和被乘数的后三位有关，与乘数和被乘数的高位无关。从这入手写就没问题了。include <stdio.h>//n次方的后三位数int main (){int x,y,i,last;last=1;//记得初始化scanf ("%d%d",&x,&y);for (i=1;i<=y;i++){...
include <stdio.h>int max(int x,int y,int z); //定义函数不能在main函数内定义void main (){int a,b,c,d;scanf("%d%d%d",&a,&b,&c);//三个地址空间，你却有四个%dd=max(a,b,c);}int max(int x,int y,int z){int m;if (x>y) m=x;else m=y;if (z>m) m=z...
include <stdio.h> void main(){ int a,b,c;printf("请输入a和b的值:");scanf("%d %d", &a, &b);c = a * b;printf("a*b = %d\n",c);}
c++编程中出现“missing function header (old-style formal list?)”是（编译错误）缺少函数标题(是否是老式的形式表？)分析：函数定义不正确，函数首部的“( )”后多了分号或者采用了老式的C语言的形参表。例如：# include <stdio.h>void main(){int max(int x,int y,int z);int a,b,c,d...
x是整形，不能那么输入，虽然不报错，但是后面的循环就不能用了。而且x的输出格式也有问题 程序修改如下：#include <stdio.h> include <math.h> void main(){ int num,x;double y,z;printf("input a number");scanf("%f",&x);printf("number squroot cubroot\n");printf("--- --- -...
include <stdio.h>int main(){double x, y;double temp;printf("input two Numbers: ");scanf("%lf %lf", &x, &y);printf("%lf, %lf\n", x, y);temp = x;x = y;y = temp;printf("%lf, %lf\n", x, y);饿...void main(){float x,y,z;scanf("%f%f",&x,&y);...
include<stdio.h> int main(){ int a,b;float x,y;char c1,c2;scanf("%d%d",&a,&b);//不要添加多余字符 scanf("%f%f",&x,&y);//float类型用%f getchar(); // 添加此句接收上一句按下的回车符 scanf("%c%c",&c1,&c2);//输入这两字符时需连在一起 输入 printf("%d ...
} else{ if(y>x&&y>z){ w=y; }else{ w=z; } } return w;}优化后的：include<stdio.h>int main(){ int max(int x,int y,int z); int a,b,c,d; scanf("%d,%d,%d",&a,&b,&c); d=max(a,b,c); printf("%d\n",d); r...
include int main(){ int a,b,c,d,e,f,x,y,z;scanf("%d",&a);if (a>9999) x=5;else if (a>999) x=4;else if (a>99) x=3;else if (a>9) x=2;else x=1;printf("位数:%d\n",x);return 0;}