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ressell&bromley
"相关结果约100,000,000个
for(int i=2;i<=n-1;i=i+2){long long int buy=min(price[i],price[i+1]);long long int sell=max(price[i],price[i+1]);if(!q.empty()){if(buy>q.top()){res=res-2*q.top()+buy+sell;q.pop();q.push(buy);q.push(sell);}else{res=res-buy+sell;q.push(sell);}...