[1,100,60000,130,-16251900,102,531,103,889,118,732,119,547,120,631,121,317,112,0,113,0,2,100,1000,130,-16777216,108,118,109,118,110,488,111,539,3,100,1106,130,-8475990,108,523,109,523,110,509,111,515,4,100,300000,124,-10078925,130,-10075326,102,377,103,0,11...
=aDn-(-1)*|(ax,-1,0,...,0)(ax^2,a,-1,...,0)...(ax^n,...,a)| 【按第一行展开】=aDn+xDn 【提出第二个行列式第一列的公因子】=(a+x) Dn 【得出《递推公式》,于是,递推:】=(a+x)^2 * D(n-1)=...=(a+x)^n * D1 =a*(a+x)^n 第...