为您找到"
log4的平方详细算法
"相关结果约100,000,000个
log以2为底(x的平方-x-2)>log以二为底(2x-2) 这题如何解? 谢谢 x>3 x^2-x-2>0 => x>2或者x<-1 2x-2>0 => x>1 且x^2-x-2>2x-2 => x>3或者x<0 联立方程求解得:x>3 祝学习愉快~log以2为底(x-1)=log以4为底x的解为 由题意,log2(x-1)=log4(x...
y=(lgx)^2-(lg12+lg3)lgx+lg3*lg12 =[lgx-(lg36)/2]^2+lg3*lg12-[(lg36)/2]=[lgx-(lg6)]^2+lg3*lg12-[(lg6)]^2 当x=6时,最小值为lg3(2lg2+lg3)-(lg2+lg3)^2=-(lg2)^2
3^x = 4 x= log4/log3 3^y = 6 y=log6/log3 2x-y+27 = 2(log4/log3) - log6/log3 + 27 = (log16-log6)/log3 + 27 = log(8/3)/log3 + 27 = log8/log3 -1 +27 = 3log2/log3 +26
an≥0 a1=1>0,假设当n=k(k∈N+)时,ak>0,则当n=k+1时 a(k+1) ^2=4ak >0 又a(k+1)≥0,因此a(k+1)>0 k为任意正整数,因此对于任意正整数n,an恒>0 //以上的判断过程必须有!不然没法确定an的正负!而且无法用对数求解!// a(n+1)^2=4an log4[a(n+1)^2]=log4(4an...
令3x=1 则x=1/3 所以f(1)=log(3x+1)²=log(1+1)²=log4
lgx+lgy=lgxy5=x+y>=2根号xyxy<=25/4y=lgx单调递增logx+logy的最大值lg(25/4)
1.3的3/4次方 2.2b 3.4 补充答案lg代表log10(10是底数,下角标)