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log4 8
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回答:解:1/2log2 3=log2^2 3=log4 3=log8 6,1/3log2 4=log2^3 4=log8 4,因为两个对数的底相同,对数6>4,所以1/2log2 3>1/3log2 4。这个log4 3=log4 3×1=log4 3+log2 2=log8 6。
log4[8] = lg8/lg4 = (3lg2)/(2lg2) = 3/2
8=4^(3/2)log4(8)=log4[4^(3/2)]=(3/2)log4(4)=3/2
log4(3)+log8(3)=log2(3)/log2(4)+log2(3)/log2(8)=0.5log2(3)+1/3*log2(3)=5/6*log2(3)在高中阶段运算到这一步化为单个对数就可以了,主要运用的是换底公式。
4^x=8 2^(2x)=2³2x=3 x=1.5
因为2^x=3,所以x=log2(3);又因为log4(8/3)=y,所以log2(8/3)=2y,即有log2(8)-log2(3)=2y,又log2(8)=3 所以2y=3-log2(3)则有x+2y=3
log4 8-log(1/9) 3-log√2 4 =log(2²)(2³)-log(3-²)3-log(2^1/2)(2²)=3/2*log₂2-(-1/2)log₃3-2/(1/2)log₂2 =3/2+1/2-4 =-2 希望帮到你